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Tardigrade
Question
Chemistry
MnO 4- is a good oxidising agent in different medium changing to MnO 4- longrightarrow Mn 2+ longrightarrow MnO 42- longrightarrow MnO 2 longrightarrow Mn 2 O 3 Changes in oxidation number respectively are :
Q.
M
n
O
4
−
is a good oxidising agent in different medium changing to
M
n
O
4
−
⟶
M
n
2
+
⟶
M
n
O
4
2
−
⟶
M
n
O
2
⟶
M
n
2
O
3
Changes in oxidation number respectively are :
1660
229
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A
1,3,4,5
B
5,4,3,2
C
5,1,3,4
D
2,6,4,3
Solution:
M
n
+
7
O
4
−
→
M
n
2
+
change 5
→
M
n
+
6
O
4
2
−
change 1
→
M
n
+
4
O
2
change 3
→
M
n
2
+
3
O
3
change 4