Mixture of volatile components A and B has total vapour pressure (in torr) P=254-119XA where, XA is mole fraction of A in mixture. Hence, PAo and PBo are (in torr)

Question

Mixture of volatile components A and B has total vapour pressure (in torr) P=254-119XA where, XA is mole fraction of A in mixture. Hence, PAo and PBo are (in torr) (A) 254, 119 (B) 119, 254 (C) 135, 254 (D) 154, 119

Tardigrade Admin · Accepted Answer

When XA=1, P=PAo So PAo=254-119=135torr When XA=0, P=PBo So PBo=254 torr.

Q. Mixture of volatile components A and B has total vapour pressure (in torr)

$P = 254 - 119 X_{A}$

where, $X_{A}$ is mole fraction of A in mixture. Hence, $P_{A}^{o}$ and $P_{B}^{o}$ are (in torr)

254, 119

119, 254

135, 254

154, 119

When $X_{A} = 1,$

$P = P_{A}^{o}$

So $P_{A}^{o} = 254 - 119 = 135 t orr$

When $X_{A} = 0,$

$P = P_{B}^{o}$

So $P_{B}^{o} = 254$ torr.

Q. Mixture of volatile components A and B has total vapour pressure (in torr) P=254−119XA​ where, XA​ is mole fraction of A in mixture. Hence, PAo​ and PBo​ are (in torr)