Minimum force required to keep a block of mass 1 kg at rest against a rough vertical wall is P. If a force P / 2 is applied then find the acceleration of the block (in m / s 2 ). (Take g=10 m / s 2 )

Question

Minimum force required to keep a block of mass 1 kg at rest against a rough vertical wall is P. If a force P / 2 is applied then find the acceleration of the block (in m / s 2 ). (Take g=10 m / s 2 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

N=P f max =0.5 P=10 N P=20 N <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/42241fcaa52de802a5f6b77e400ca57d-.png" /> If applied force is (P/2), i.e. 10 N, 10-(0.5)(10)=10 × a a=5 m / s 2

Q. Minimum force required to keep a block of mass $1 k g$ at rest against a rough vertical wall is $P$ . If a force $P /2$ is applied then find the acceleration of the block (in $m / s^{2}$ ). (Take $g = 10 m / s^{2}$ )

$N = P$
$f_{m a x} = 0.5 P = 10 N$
$P = 20 N$

If applied force is $\frac{P}{2}$ , i.e. $10 N$ ,
$10 - (0.5) (10) = 10 \times a$
$a = 5 m / s^{2}$

Q. Minimum force required to keep a block of mass 1kg at rest against a rough vertical wall is P. If a force P/2 is applied then find the acceleration of the block (in m/s2 ). (Take g=10m/s2 )

N=P fmax​=0.5P=10N P=20N If applied force is 2P​, i.e. 10N, 10−(0.5)(10)=10×a a=5m/s2

Q. Minimum force required to keep a block of mass $1 k g$ at rest against a rough vertical wall is $P$ . If a force $P /2$ is applied then find the acceleration of the block (in $m / s^{2}$ ). (Take $g = 10 m / s^{2}$ )

$N = P$
$f_{m a x} = 0.5 P = 10 N$
$P = 20 N$

If applied force is $\frac{P}{2}$ , i.e. $10 N$ ,
$10 - (0.5) (10) = 10 \times a$
$a = 5 m / s^{2}$