Minimum deviation is observed with a prism having angle of prism A, angle of deviation δ , angle of incident i and angle of emergence e, then we have generally:

Question

Minimum deviation is observed with a prism having angle of prism A, angle of deviation δ , angle of incident i and angle of emergence e, then we have generally: (A)  i=e  (B)  i< e  (C)  i>e  (D)  i=e=0

Tardigrade Admin · Accepted Answer

A prism which has angle of prism A angle of deviation δ , angle of incidence i and angle of emergence e, then the minimum deviation is observed if we have generally angle of incidence i= angle of emergence e .

Q. Minimum deviation is observed with a prism having angle of prism A, angle of deviation $δ,$ angle of incident $i$ and angle of emergence e, then we have generally:

$i = e$

$i < e$

$i > e$

$i = e = 0$

A prism which has angle of prism A angle of deviation $δ,$ angle of incidence $i$ and angle of emergence $e,$ then the minimum deviation is observed if we have generally angle of incidence $i =$ angle of emergence $e$ .

Q. Minimum deviation is observed with a prism having angle of prism A, angle of deviation δ, angle of incident i and angle of emergence e, then we have generally:

i=e

i<e

i>e

i=e=0