Question

Maximum value of spin multiplicity for electrons in $Cr$ atom is -

• A. $5$
• B. $2$
• C. $3$
• D. $7$

Answer 1

Answer: (D)

$Cr(24)=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}4s^1$
Spin multiplicity $=2\left|\frac{6}{2}\right|+1=7$