Lowering of vapour, pressure, Δ p : elevation in boiling point. Δ Tb : and depression in freezing point, Δ Tf of a solvent for the same molar concentration of each of the three solutes: [A] sugar, [B] NaCl, and [C] BaCl2 follow the sequence:

Question

Lowering of vapour, pressure, Δ p : elevation in boiling point. Δ Tb : and depression in freezing point, Δ Tf of a solvent for the same molar concentration of each of the three solutes: [A] sugar, [B] NaCl, and [C] BaCl2 follow the sequence: (A) Δ p:AB>A (C) Δ Tf:A

Tardigrade Admin · Accepted Answer

: If solute dissociates in the solution, e.g. NaCl,MgCl2,BaCl2 etc., the number of particles in solution will be more than that actually dissolved and value of colligative properties will be higher.

Q. Lowering of vapour, pressure, $Δ p$ : elevation in boiling point. $Δ T_{b}$ : and depression in freezing point, $Δ T_{f}$ of a solvent for the same molar concentration of each of the three solutes: [A] sugar, [B] $N a Cl,$ and [C] $B a C l_{2}$ follow the sequence:

$Δ p : A < B < C$

$Δ T_{b} : C > B > A$

$Δ T_{f} : A < B < C$

all of these

: If solute dissociates in the solution, e.g. $N a Cl, M g C l_{2}, B a C l_{2}$ etc., the number of particles in solution will be more than that actually dissolved and value of colligative properties will be higher.

Q. Lowering of vapour, pressure, Δp : elevation in boiling point. ΔTb​ : and depression in freezing point, ΔTf​ of a solvent for the same molar concentration of each of the three solutes: [A] sugar, [B] NaCl, and [C] BaCl2​ follow the sequence:

Δp:A<B<C

ΔTb​:C>B>A

ΔTf​:A<B<C