Liquefied natural gas (LNG) is mainly methane. A 10 m3 tank is constructed to store LNG at —164°C and 1 atm pressure, under this condition density of LNG is 415 kg/m3. The volume of storage tank capable of holding --- mass of LNG as a gas at 20°C and 1 atm pressure will be

Question

Liquefied natural gas (LNG) is mainly methane. A 10 m3 tank is constructed to store LNG at —164°C and 1 atm pressure, under this condition density of LNG is 415 kg/m3. The volume of storage tank capable of holding --- mass of LNG as a gas at 20°C and 1 atm pressure will be (A) 1250 m3 (B) 5280 m3 (C) 6230 m3 (D) 9870 m3

Tardigrade Admin · Accepted Answer

n=(10×415×1000/16)=2.59×105 V=(nRT/P)=(2.59×105×0.0821×293/1) =6.23×106 L=6230 m3

$1250 m^{3}$

$5280 m^{3}$

$6230 m^{3}$

$9870 m^{3}$

$n = \frac{10 \times 415 \times 1000}{16} = 2.59 \times 1 0^{5}$
$V = \frac{n RT}{P} = \frac{2.59 \times 1 0 ^{5} \times 0.0821 \times 293}{1}$
$= 6.23 \times 1 0^{6} L = 6230 m^{3}$

Q. Liquefied natural gas (LNG) is mainly methane. A 10m3 tank is constructed to store LNG at —164∘C and 1atm pressure, under this condition density of LNG is 415kg/m3. The volume of storage tank capable of holding --- mass of LNG as a gas at 20∘C and 1atm pressure will be

1250m3

5280m3

6230m3

9870m3

n=1610×415×1000​=2.59×105 V=PnRT​=12.59×105×0.0821×293​ =6.23×106L=6230m3

$1250 m^{3}$

$5280 m^{3}$

$6230 m^{3}$

$9870 m^{3}$

$n = \frac{10 \times 415 \times 1000}{16} = 2.59 \times 1 0^{5}$
$V = \frac{n RT}{P} = \frac{2.59 \times 1 0 ^{5} \times 0.0821 \times 293}{1}$
$= 6.23 \times 1 0^{6} L = 6230 m^{3}$