Question

${\lim }_{x\to 2}\frac{2x^2-5x+2}{x^2-3x+2}$

• A. 1
• B. 2
• C. 3
• D. 8

Answer 1

Answer: (C)

${\lim }_{x\to 2}\frac{2x^2-5x+2}{x^2-3x+2}={\lim }_{x\to 2}\frac{\left(x-2\right)\left(2x-1\right)}{\left(x-2\right)\left(x-1\right)}$
${\lim }_{x\to 2}\frac{2x-1}{x-1}=\frac{4-1}{2-1}=3$