Question

${\lim }_{x\to 0+}\frac{sin,x}{\sqrt{x}}$is

• A. 0
• B. $\frac{1}{2}$
• C. 1
• D. does not exist

Answer 1

Answer: (A)

${\lim }_{x\to 0+}\frac{\sin x}{\sqrt{x}}={\lim }_{x\to 0+}\frac{\sin x}{x}.\sqrt{x}=1\left(0\right)=0$