Question

Let $y=f(x)$ be a real-valued differentiable function on $R$ (the set of all real numbers) such that $f(1)=1$. If $f(x)$ satisfies $x{f}^{\prime }(x)=x^2+f(x)-2$ then find the area enclosed by $f(x)$ with $x$-axis between ordinates $x=0$ and $x=3$.

Answer 1

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