Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Let Xn denote the mean of first n natural numbers, then the mean of X1,X2, ldots ,X100 is
Q. Let
X
n
denote the mean of first
n
natural numbers, then the mean of
X
1
,
X
2
,
…
,
X
100
is
1250
238
NTA Abhyas
NTA Abhyas 2020
Statistics
Report Error
A
25
0%
B
50
88%
C
25.5
0%
D
25.75
12%
Solution:
X
n
=
n
r
=
1
∑
n
r
=
2
n
n
(
n
+
1
)
=
2
n
+
1
n
n
=
1
∑
100
X
n
=
200
2
100
×
101
+
100
=
4
101
+
2
1
=
25.75