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Question
Mathematics
Let x= cos (π/3)+i sin (π/3) and Δ=| 1 x x2 x2 1 x 1 x2 1 | then numerical value of Δ is
Q. Let
x
=
cos
3
π
+
i
sin
3
π
and
Δ
=
∣
∣
1
x
2
1
x
1
x
2
x
2
x
1
∣
∣
then numerical value of
Δ
is
125
116
Determinants
Report Error
A
0
B
-1
C
8
D
-4
Solution:
Use
C
3
→
C
3
−
x
C
2
and
C
2
→
C
2
−
x
C
1
.
Δ
=
∣
∣
1
x
2
1
0
1
−
x
3
x
2
−
x
0
0
1
−
x
3
<
b
r
/
>
∣
∣
=
(
1
−
x
3
)
2
=
[
1
−
cos
π
−
i
sin
π
]
2
=
8
[De Moivre's Theorem]