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Question
Mathematics
Let veca ×( vecb × vecc)=( vecb/3)+( vecc/2) and vecb ×( vecc × veca)=-( vecc/2). If veca, vecb and vecc are non-collinear pairwise unit vectors, then volume of a parallelepiped, whose coterminous edges are veca, vecb and vecc, is
Q. Let
a
×
(
b
×
c
)
=
3
b
+
2
c
and
b
×
(
c
×
a
)
=
−
2
c
. If
a
,
b
and
c
are non-collinear pairwise unit vectors, then volume of a parallelepiped, whose coterminous edges are
a
,
b
and
c
, is
75
158
Vector Algebra
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A
36
11
B
2
1
C
36
23
D
None of these
Solution:
a
×
(
b
×
c
)
=
3
b
+
2
c
⇒
(
a
⋅
c
)
b
−
(
a
⋅
b
)
c
=
3
b
+
2
c
⇒
a
⋅
c
=
3
1
and
a
⋅
b
=
−
2
1
Also
b
×
(
c
×
a
)
=
−
2
c
⇒
(
b
⋅
a
)
c
−
(
b
⋅
c
)
a
=
−
2
c
⇒
b
⋅
c
=
0
Volume of parallelepiped
=
∣
[
a
b
c
]
∣
[
a
b
c
]
2
=
∣
∣
a
⋅
a
b
⋅
a
c
⋅
a
a
⋅
b
b
⋅
b
c
⋅
b
a
⋅
c
b
⋅
c
c
⋅
c
∣
∣
=
∣
∣
1
−
2
1
3
1
−
2
1
1
0
3
1
0
1
∣
∣
=
36
23
Volume
=
6
23