Clearly, A′={1,4,5,6},B′={1,2,6}.
Hence, A′∩B′={1,6}.
Also, A∪B={2,3,4,5}, so that (A∪B)={1,6} (A∪B)′={1,6}=A′∩B′
It can be shown that the above result is true in general. If A and B are any two subsets of the universal set U, then (A∪B)′=A′∩B′
Similarly, (A∩B)′=A′∪B′