Let three dice be thrown once. A, B and C three events are defined as A: Sum on the dice is divisible by 6. B: Sum on the dice has maximum number of divisors. C: Sum on two of the dice is 11 or more The value of P (( B / A )) is equal to

Question

Let three dice be thrown once. A, B and C three events are defined as A: Sum on the dice is divisible by 6. B: Sum on the dice has maximum number of divisors. C: Sum on two of the dice is 11 or more The value of P (( B / A )) is equal to (A) (25/36) (B) (26/36) (C) (27/36) (D) (25/216)

Tardigrade Admin · Accepted Answer

A: sum on dice is 6, 12, 18 B: sum on dice is 12, 18 (12 and 18 has maximum number of divisors) C: sum on two of the dice is 11 or more ∴ It is 12,13, ldots ldots 18. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/c8626eab3f1c28703c69876765d1dd1e-.png" /> P (( B / A ))=( P ( text sum 12 text or 18)/ P ( textsum 6 text or 12 text or 18))=(25+1/25+1+10)=(26/36)

Q. Let three dice be thrown once. A, B and C three events are defined as
A : Sum on the dice is divisible by 6.
B : Sum on the dice has maximum number of divisors.
C : Sum on two of the dice is 11 or more
The value of $P (\frac{B}{A})$ is equal to

$\frac{25}{36}$

$\frac{26}{36}$

$\frac{27}{36}$

$\frac{25}{216}$

A : sum on dice is 6, 12, 18
B : sum on dice is 12, 18
(12 and 18 has maximum number of divisors)
C : sum on two of the dice is 11 or more
$∴$ It is $12, 13, \dots\dots 18$ .

$P (\frac{B}{A}) = \frac{P ( sum 12 or 18 )}{P ( sum 6 or 12 or 18 )} = \frac{25 + 1}{25 + 1 + 10} = \frac{26}{36}$

Q. Let three dice be thrown once. A, B and C three events are defined as A : Sum on the dice is divisible by 6. B : Sum on the dice has maximum number of divisors. C : Sum on two of the dice is 11 or more The value of P(AB​) is equal to

3625​

3626​

3627​

21625​