Let the initial concentration of P is 1 M, the concentration of P after 33.33 sec is equal to?

Question

<img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-9ka1wiejfanxzju8.jpg" /> Let the initial concentration of P is 1 M, the concentration of P after 33.33 sec is equal to? (A) (1/e) (B) (2/e) (C) (1/e2) (D) e

Tardigrade Admin · Accepted Answer

keff=k1+k2=3× 10- 2s- 1 (P)t=1× e- k t =e- 3 × 1 0- 2 × 33.3 =e- 0.99=(1/e)

Q.
Let the initial concentration of $P$ is $1 M$ , the concentration of $P$ after $33.33 sec$ is equal to?

$\frac{1}{e}$

$\frac{2}{e}$

$\frac{1}{e ^{2}}$

$e$

$k_{e ff} = k_{1} + k_{2} = 3 \times 1 0^{- 2} s^{- 1}$
$(P)_{t} = 1 \times e^{- k t}$
$= e^{- 3 \times 1 0^{- 2} \times 33.3}$
$= e^{- 0.99} = \frac{1}{e}$

Q. Let the initial concentration of P is 1M, the concentration of P after 33.33sec is equal to?

e1​

e2​

e21​

e

keff​=k1​+k2​=3×10−2s−1 (P)t​=1×e−kt =e−3×10−2×33.3 =e−0.99=e1​

Q.
Let the initial concentration of $P$ is $1 M$ , the concentration of $P$ after $33.33 sec$ is equal to?

$\frac{1}{e}$

$\frac{2}{e}$

$\frac{1}{e ^{2}}$

$e$

$k_{e ff} = k_{1} + k_{2} = 3 \times 1 0^{- 2} s^{- 1}$
$(P)_{t} = 1 \times e^{- k t}$
$= e^{- 3 \times 1 0^{- 2} \times 33.3}$
$= e^{- 0.99} = \frac{1}{e}$