Let p = displaystyle∑ n =19 sin 2(( n π/24)) and q = displaystyle∑ n =19 cos 2(( n π/24)), then find the value of (p+q).

Question

Let p = displaystyle∑ n =19 sin 2(( n π/24)) and q = displaystyle∑ n =19 cos 2(( n π/24)), then find the value of (p+q). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

p + q = displaystyle∑ n =19 sin 2(( n π/24))+∑ n =19 cos 2(( n π/24)) = displaystyle∑ n =19[ sin 2(( n π/24))+ cos 2(( n π/24))]=∑ n =19 1=9

Q. Let $p = n = 1 \sum 9 sin^{2} (\frac{nπ}{24})$ and $q = n = 1 \sum 9 cos^{2} (\frac{nπ}{24})$ , then find the value of $(p + q)$ .