Let P1 be a parabola with vertex (3,2) and focus (4,4) and P2 be its mirror image with respect to the line x +2 y =6. Then the directrix of P 2 is x +2 y = .

Question

Let P1 be a parabola with vertex (3,2) and focus (4,4) and P2 be its mirror image with respect to the line x +2 y =6. Then the directrix of P 2 is x +2 y = . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

P1: Directorix: x +2 y = k x +2 y - k =0 |(3+4- K /√5)|=√5 |7- k |=5

Q. Let $P_{1}$ be a parabola with vertex $(3, 2)$ and focus $(4, 4)$ and $P_{2}$ be its mirror image with respect to the line $x + 2 y = 6$ . Then the directrix of $P_{2}$ is $x + 2 y =$ ______.

$P_{1} :$ Directorix :
$x + 2 y = k$
$x + 2 y - k = 0$
$∣ ∣ \frac{3 + 4 - K}{5} ∣ ∣ = 5$
$∣7 - k ∣ = 5$

Q. Let P1​ be a parabola with vertex (3,2) and focus (4,4) and P2​ be its mirror image with respect to the line x+2y=6. Then the directrix of P2​ is x+2y= ______.

P1​: Directorix : x+2y=k x+2y−k=0 ∣∣​5​3+4−K​∣∣​=5​ ∣7−k∣=5

Q. Let $P_{1}$ be a parabola with vertex $(3, 2)$ and focus $(4, 4)$ and $P_{2}$ be its mirror image with respect to the line $x + 2 y = 6$ . Then the directrix of $P_{2}$ is $x + 2 y =$ ______.

$P_{1} :$ Directorix :
$x + 2 y = k$
$x + 2 y - k = 0$
$∣ ∣ \frac{3 + 4 - K}{5} ∣ ∣ = 5$
$∣7 - k ∣ = 5$