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Tardigrade
Question
Mathematics
Let N = log 10(√( cos 30°-1)2+√(2 tan 30°+1)2-4 sin 30°). Then N is
Q. Let
N
=
lo
g
10
(
(
cos
3
0
∘
−
1
)
2
+
(
2
tan
3
0
∘
+
1
)
2
−
4
sin
3
0
∘
)
. Then
N
is
37
97
Continuity and Differentiability
Report Error
A
a negative real number
B
a positive real number
C
not real or meaningless in logarithm
D
0
Solution:
lo
g
10
(
(
1
−
2
3
)
+
(
3
2
+
1
)
−
2
)
=
3
2
−
2
3
=
lo
g
10
(
2
3
1
)
\{negative real
}