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Tardigrade
Question
Mathematics
Let l= underset x arrow 0+ textLim x m ( ln x ) n where m , n ∈ N then :
Q. Let
l
=
x
→
0
+
Lim
x
m
(
ln
x
)
n
where
m
,
n
∈
N
then :
122
95
Continuity and Differentiability
Report Error
A
l is independent of m and n
B
l is independent of m and depends on m
C
l is independent of n and dependent on m
D
l is dependent on both m and n
Solution:
l
=
x
→
0
+
Lim
x
−
m
(
l
n
x
)
n
Using L'Hospital's rule
l
x
→
0
+
Lim
m
n
n
!
(
−
1
)
n
x
m
=
0