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Tardigrade
Question
Mathematics
Let f( x )= x + sin x. Suppose g denotes the inverse function of f. The value of g prime((π/4)+(1/√2)) has the value equal to
Q. Let
f
(
x
)
=
x
+
sin
x
. Suppose
g
denotes the inverse function of
f
. The value of
g
′
(
4
π
+
2
1
)
has the value equal to
838
91
Continuity and Differentiability
Report Error
A
2
−
1
B
2
2
+
1
C
2
−
2
D
2
+
1
Solution:
f
(
x
)
=
y
=
x
+
sin
x
d
x
d
y
=
1
+
cos
x
g
′
(
y
)
=
d
y
d
x
=
1
+
c
o
s
x
1
where
y
=
4
π
+
2
1
=
x
+
sin
x
⇒
x
=
4
π
∴
g
′
(
4
π
+
2
1
)
=
1
+
(
1/
2
)
1
=
2
+
1
2
=
2
(
2
−
1
)
=
2
−
2