Let f(x)= begincasesx3+x2-10 x ; -1 ≤ x

Question

Let f(x)= begincasesx3+x2-10 x ; -1 ≤ x < 0 sin x ; 0 ≤ x < π / 2 1+ cos x ; π / 2 ≤ x ≤ π endcases, then f(x) has (A) local minimum at x=π / 2 (B) local minima at x =-1 (C) absolute minima at x=0, π (D) absolute maxima at x=π / 2

Tardigrade Admin · Accepted Answer

Correct answer is (c) absolute minima at x=0, π

Q. Let $f (x) = ⎩ ⎨ ⎧ x^{3} + x^{2} - 10 x; sin x; 1 + cos x; - 1 \leq x < 0 0 \leq x < π /2 π /2 \leq x \leq π$ , then $f (x)$ has

local minimum at $x = π /2$

local minima at $x = - 1$

absolute minima at $x = 0, π$

absolute maxima at $x = π /2$

Correct answer is (c) absolute minima at $x = 0, π$

Q. Let f(x)=⎩⎨⎧​x3+x2−10x;sinx;1+cosx;​−1≤x<00≤x<π/2π/2≤x≤π​, then f(x) has

local minimum at x=π/2

local minima at x=−1

absolute minima at x=0,π

absolute maxima at x=π/2