sin−1−cos−1x=2sin−1x−π/2 f(x):(2sin−1x−π/2) so 2sin−1x−π/2≥0⇒sin−1x≥π/4
so Domain of, f(x):21≤x≤1 similarly g(x)=(2tan−1x−2π),tan−1x≥4π
so Domain of, g(x):1≤x<∞ similarly h(x)=(2sec−1x−2π),sec−1x≥4π
so Domain of, h(x):(−∞,−1]∪[2,∞) so Domain of f(x)+g(x) is 1 only.
for g(x)+h(x) Domain will be [2,∞),
for h(x)+f(x), Domain will be null set
for g(x)+h(x)+f(x), Domain will be null set .