Let f(x) = log (x + √x2 + 1) , then f'(x) equals

Question

Let f(x) = log (x + √x2 + 1) , then f'(x) equals (A) √x2 + 1 (B) (x/√x2 + 1) (C)  1 + (x/√x2 + 1) (D) (1/√x2 + 1)

Tardigrade Admin · Accepted Answer

f'(x) = (1/x+√x2+1) [ 1+ (1.2 x/2√x2 + 1) ] = (1/√x2+1)

Q. Let $f (x) = lo g (x + x^{2} + 1)$ , then $f^{'} (x)$ equals