Q.
Let f:R→R be defined as f(x)=sinπ[x]+e−∣x∣−ex, then f(x) is [Note: [x] denotes the largest integer less than or equal to x.]
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126
Relations and Functions - Part 2
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Solution:
We have f(x)=e−∣x∣−ex( As sinπ[x]=0∀x∈R) ={0e−x−ex;x<0;x≥0
Clearly, f(x) is many-one and into function. So, f(x) is neither injective nor surjective.