Tardigrade
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Tardigrade
Question
Mathematics
Let curve C is such that length of subnormal at any point of the curve is 2 and curve passes through the point P(1,2), and Q(4,4) then
Q. Let curve
C
is such that length of subnormal at any point of the curve is 2 and curve passes through the point
P
(
1
,
2
)
, and
Q
(
4
,
4
)
then
204
161
Application of Integrals
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A
length of subtangent at point
P
is 2
59%
B
area bounded by
C
with line
x
=
1
is
3
8
52%
C
length of subtangent at point
P
is 4
15%
D
area bounded by
C
with line
x
=
1
is
3
4
111%
Solution:
∣
m
y
∣
=
2
⇒
y
d
y
=
2
d
x
⇒
2
y
2
=
2
x
+
C
∴
y
2
=
4
x
⇒
P
(
t
2
,
2
t
)
∴
ST
=
2
t
2
2
2
t
=
2
t
2
=
2
A
=
2
0
∫
1
2
x
d
x
=
2
3
4
⋅
(
x
2
3
)
0
1
=
3
8
Θ
y
d
x
d
y
=
2
∴
Orthogonal trajectory is
y
d
y
d
x
=
−
2
⇒
−
2
y
d
y
=
d
x
⇒
−
2
ln
y
=
x
+
λ
⇒
y
=
α
⋅
e
2
−
x
.