Let A = x: x2 - 5x + 6 = 0 B = 2,4 C = 4, 5 then A × (B ∩ C) is

Question

Let A = x: x2 - 5x + 6 = 0 B = 2,4 C = 4, 5 then A × (B ∩ C) is (A)  (2,4), (3,4)  (B)  (4, 2), (4, 3)  (C)  (2, 4), (3,4), (4,4)  (D)  (2,2), (3,3), (4,4), (5,5)

Tardigrade Admin · Accepted Answer

A = x: x2 - 5x + 6 = 0 x2 - 5x + 6 = 0 ⇒ (x - 3) (x - 2) = 0 ⇒ x = 3, 2 ∴ A = 3,2 B = 2,4 C = 4, 5 Now, B∩ C= 4 ⇒ A × (B ∩ C)= 3,2 × 4 = (3, 4), (2, 4) .

Q. Let $A = {x : x^{2} - 5 x + 6 = 0}$ , $B = {2, 4}$ , $C = {4, 5}$ then $A \times (B \cap C)$ is

${(2, 4), (3, 4)}$

${(4, 2), (4, 3)}$

${(2, 4), (3, 4), (4, 4)}$

${(2, 2), (3, 3), (4, 4), (5, 5)}$

$A = {x : x^{2} - 5 x + 6 = 0}$
$x^{2} - 5 x + 6 = 0$
$\Rightarrow (x - 3) (x - 2) = 0$
$\Rightarrow x = 3, 2$
$∴ A = {3, 2}, B = {2, 4}, C = {4, 5}$
Now, $B \cap C = {4}$
$\Rightarrow A \times (B \cap C) = {3, 2} \times {4}$
$= {(3, 4), (2, 4)}$ .

Q. Let A={x:x2−5x+6=0}, B={2,4}, C={4,5} then A×(B∩C) is

{(2,4),(3,4)}

{(4,2),(4,3)}

{(2,4),(3,4),(4,4)}

{(2,2),(3,3),(4,4),(5,5)}