r×a=b×a ⇒(r−b)×a=0 ⇒r−b is paralllel to a ∴r−b=λa
i.e. r=b+λa(1)
Similarly, r×b=a×b can be written as r=a+μb(2)
For point of intersection of the two lines (1) and (2),
we get b+λa=a+μb ⇒λ=μ=1
Hence, the required point of intersection is given by r=a+b=i+j+2i−k=3i+j−k