(1+z)3 where z=x(1+2x+3x2) 1+3C1z+3C2z2+3C3z3 coefficient of x3 in (1+z)3 3C1(3)+3C2(4)+3C3(1)=22 ⇒a=22 now again (1+y)3 where y=x(1+2x+3x2+4x3) (1+y)3=1+3C1y+3C2y2+3C3y3 ∴ coefficient of x3 is 3C1(3)+3C2(4)+3C3(1) =9+12+1=22 ⇒b=22 Hence a =b⇒a+b=44