Kp for the reaction, N2O4(g)leftharpoons 2NO2(g) is 0.157 atm at 27° C and 1 atm pressure. Kc for this reaction is

Question

Kp for the reaction, N2O4(g)leftharpoons 2NO2(g) is 0.157 atm at 27° C and 1 atm pressure. Kc for this reaction is (A)  6.37× 10-3  (B)  4.29× 10-3  (C)  5.62× 10-3  (D)  4.37× 10-3

Tardigrade Admin · Accepted Answer

Δ ng=np-nr=2-1=1, Kc=(Kp/(RT)Δ ng) =((0.157 atm)/(0.0821 L atm K-1 mol-1 × 300 K)1) =6.37× 10-3 mol L-1

Q. $K_{p}$ for the reaction, $N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)$ is 0.157 atm at $27^{\circ} C$ and 1 atm pressure. $K_{c}$ for this reaction is

$6.37 \times 10^{- 3}$

$4.29 \times 10^{- 3}$

$5.62 \times 10^{- 3}$

$4.37 \times 10^{- 3}$

$Δ n_{g} = n_{p} - n_{r} = 2 - 1 = 1,$ $K_{c} = \frac{K _{p}}{( RT ) ^{Δ n_{g}}}$ $= \frac{( 0.157 a t m )}{( 0.0821 L a t m K ^{- 1} m o l ^{- 1} \times 300 K ) ^{1}}$ $= 6.37 \times 10^{- 3} m o l L^{- 1}$

Q. Kp​ for the reaction, N2​O4​(g)⇌2NO2​(g) is 0.157 atm at 27∘C and 1 atm pressure. Kc​ for this reaction is

6.37×10−3

4.29×10−3

5.62×10−3

4.37×10−3