Isobutyl magnesium bromide with dry ether and ethyl alcohol gives:

Question

Isobutyl magnesium bromide with dry ether and ethyl alcohol gives: (A) CH3 - underset overset|CH3CH-CH2 OHand CH3 CH2 MgBr (B) CH3 - underset overset|CH3CH-CH3 and MgBr(OC2H5) (C) CH3 - underset overset|CH3CH-CH=CH2and Mg (OH)Br (D) CH3 - underset overset|CH3CH-CH3and CH3CH2 OMgBr

Tardigrade Admin · Accepted Answer

(CH3)2 CHCH2MgBr xrightarrowC2H5OH (CH3)2 CHCH3 +C2 H5 OMgBr as R of Grignard’s reagent will take proton and form alkane.

Q. Isobutyl magnesium bromide with dry ether and ethyl alcohol gives:

$C H_{3} - C H_{3} ∣ C H - C H_{2} O H$ and $C H_{3} C H_{2} M g B r$

$C H_{3} - C H_{3} ∣ C H - C H_{3}$ and $M g B r (O C_{2} H_{5})$

$C H_{3} - C H_{3} ∣ C H - C H = C H_{2}$ and $M g (O H) B r$

$C H_{3} - C H_{3} ∣ C H - C H_{3}$ and $C H_{3} C H_{2} OM g B r$

$(C H_{3})_{2} C H C H_{2} M g B r C_{2} H_{5} O H (C H_{3})_{2} C H C H_{3} + C_{2} H_{5} OM g B r$
as $R$ of Grignard’s reagent will take proton and form alkane.

Q. Isobutyl magnesium bromide with dry ether and ethyl alcohol gives:

CH3​−CH3​∣​CH​−CH2​OHand CH3​CH2​MgBr

CH3​−CH3​∣​CH​−CH3​and MgBr(OC2​H5​)

CH3​−CH3​∣​CH​−CH=CH2​and Mg(OH)Br

CH3​−CH3​∣​CH​−CH3​and CH3​CH2​OMgBr

(CH3​)2​CHCH2​MgBrC2​H5​OH​(CH3​)2​CHCH3​+C2​H5​OMgBr as R of Grignard’s reagent will take proton and form alkane.

$C H_{3} - C H_{3} ∣ C H - C H_{2} O H$ and $C H_{3} C H_{2} M g B r$

$C H_{3} - C H_{3} ∣ C H - C H_{3}$ and $M g B r (O C_{2} H_{5})$

$C H_{3} - C H_{3} ∣ C H - C H = C H_{2}$ and $M g (O H) B r$

$C H_{3} - C H_{3} ∣ C H - C H_{3}$ and $C H_{3} C H_{2} OM g B r$

$(C H_{3})_{2} C H C H_{2} M g B r C_{2} H_{5} O H (C H_{3})_{2} C H C H_{3} + C_{2} H_{5} OM g B r$
as $R$ of Grignard’s reagent will take proton and form alkane.