Iron crystallises in a bcc system with a lattice parameter of text2 text.861 overset texto mathop textA . Calculate the density of iron in the bcc system (atomic weight of textFe=56, textN textA=6.02× 1023 textmo textl-1 ).

Question

Iron crystallises in a bcc system with a lattice parameter of text2 text.861 overset texto mathop textA . Calculate the density of iron in the bcc system (atomic weight of textFe=56, textN textA=6.02× 1023 textmo textl-1 ). (A)  7.94g mL-1  (B)  8.96 textg textm textL-1  (C)  2.78 textg textm textL-1  (D)  6.72 textg textm textL-1

Tardigrade Admin · Accepted Answer

d=(ZM/NAa3) (for bcc, Z=2 ) dFe=((2)× 56.0 g mol-1/(6.02× 1023mol-1)(2.861× 10-8)3cm3) =7.94 g ML-1

Q. Iron crystallises in a bcc system with a lattice parameter of $2 .861 A o .$ Calculate the density of iron in the bcc system (atomic weight of $Fe = 56, N_{A} = 6.02 \times 10^{23} mo l^{- 1}$ ).

$7.94 g m L^{- 1}$

$8.96 g m L^{- 1}$

$2.78 g m L^{- 1}$

$6.72 g m L^{- 1}$

$d = \frac{ZM}{N _{A} a ^{3}}$ (for bcc, $Z = 2$ )
$d_{F e} = \frac{( 2 ) \times 56.0 g m o l ^{- 1}}{( 6.02 \times 10 ^{23} m o l ^{- 1} ) ( 2.861 \times 10 ^{- 8} ) ^{3} c m ^{3}}$
$= 7.94 g M L^{- 1}$

Q. Iron crystallises in a bcc system with a lattice parameter of 2.861Ao. Calculate the density of iron in the bcc system (atomic weight of Fe=56,NA​=6.02×1023mol−1 ).

7.94gmL−1

8.96gmL−1

2.78gmL−1

6.72gmL−1