∫ sin (11 x) ⋅ sin 9 x d x=+C

Question

∫ sin (11 x) ⋅ sin 9 x d x=+C (A) ( sin (10 x) ⋅ sin 10 x/10) (B) ( sin 11 x/11) (C) ( sin (9 x) ⋅ sin 9 x/9) (D) ( cos (10 x) ⋅ cos 10 x/10)

Tardigrade Admin · Accepted Answer

∫ sin (10 x+x) sin 9 x dx ∫ sin 10 x cos x sin 9 x dx +∫ cos 10 x sin 10 x dx ( sin 10 x/10) sin 10 x-(10/10) ∫ sin 10 x cos 10 x d x+∫ cos (10 x) sin 10 x d x ( sin 10 x/10) sin (10 x)+C

Q. $\int sin (11 x) \cdot sin^{9} x d x = + C$

$\frac{s i n ( 10 x ) \cdot s i n ^{10} x}{10}$

$\frac{s i n ^{11} x}{11}$

$\frac{s i n ( 9 x ) \cdot s i n ^{9} x}{9}$

$\frac{c o s ( 10 x ) \cdot c o s ^{10} x}{10}$

$\int sin (10 x + x) sin^{9} x d x$
$\int sin 10 x cos x sin^{9} x d x + \int cos 10 x sin^{10} x d x$
$\frac{s i n ^{10} x}{10} sin 10 x - \frac{10}{10} \int sin^{10} x cos 10 x d x + \int cos (10 x) sin^{10} x d x$
$\frac{s i n ^{10} x}{10} sin (10 x) + C$

Q. ∫sin(11x)⋅sin9xdx=+C

10sin(10x)⋅sin10x​

11sin11x​

9sin(9x)⋅sin9x​

10cos(10x)⋅cos10x​