∫ e3x sin 2x dx equals

Question

∫ e3x sin 2x dx equals (A) (e3x/13) (3 cos 2x + 2 cos 2x) + c (B) (e3x/13) (3 sin 2x - 2 cos 2x) + c (C) (e3x/13) (-3 cos 2x - 2 cos 2x) + c (D) (e3x/13) (3 sin 2x + 2 cos 2x) + c

Tardigrade Admin · Accepted Answer

Correct answer is (b) (e3x/13) (3 sin 2x - 2 cos 2x) + c

Q. $\int e^{3 x} s in 2 x d x$ equals

$\frac{e ^{3 x}}{13} (3 cos 2 x + 2 cos 2 x) + c$

$\frac{e ^{3 x}}{13} (3 s in 2 x - 2 cos 2 x) + c$

$\frac{e ^{3 x}}{13} (- 3 cos 2 x - 2 cos 2 x) + c$

$\frac{e ^{3 x}}{13} (3 s in 2 x + 2 cos 2 x) + c$

Correct answer is (b) $\frac{e ^{3 x}}{13} (3 s in 2 x - 2 cos 2 x) + c$

Q. ∫e3xsin2xdx equals

13e3x​(3cos2x+2cos2x)+c

13e3x​(3sin2x−2cos2x)+c

13e3x​(−3cos2x−2cos2x)+c

13e3x​(3sin2x+2cos2x)+c