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Question
Mathematics
∫01| sin 2π x|dx is equal to
Q.
∫
0
1
∣
sin
2
π
x
∣
d
x
is equal to
2068
186
Jharkhand CECE
Jharkhand CECE 2011
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A
0
B
−
π
1
C
π
1
D
π
2
Solution:
I
=
∫
0
1
∣
sin
2
π
x
∣
d
x
=
∫
0
1/2
(
sin
2
π
x
)
d
x
+
∫
1/2
1
−
(
sin
2
π
x
)
d
x
=
−
2
π
1
[
cos
2
π
x
]
0
1/2
+
2
π
1
[
cos
2
π
x
]
1/2
1
=
π
2