In which of the following reactions, there is no change in valency ?

Question

In which of the following reactions, there is no change in valency ? (A) 4 KClO 3 longrightarrow 3 KClO 4+ KCl (B) SO 2+2 H 2 S longrightarrow 2 H 2 O +3 S (C) BaO 2+ H 2 SO 4 longrightarrow BaSO 4+ H 2 O 2 (D) 3 BaO + O 2 longrightarrow 2 BaO 2

Tardigrade Admin · Accepted Answer

BaO 2+ H 2 SO 4 arrow BaSO 4+ H 2 O 2 as we know oxygen in peroxide is hare -1 oxidotion. SO, BaO 2 and H 2 O 2 are peroxide have -1 oxidation in oxygen.

Q. In which of the following reactions, there is no change in valency ?

$4 K Cl O_{3} ⟶ 3 K Cl O_{4} + K Cl$

$S O_{2} + 2 H_{2} S ⟶ 2 H_{2} O + 3 S$

$B a O_{2} + H_{2} S O_{4} ⟶ B a S O_{4} + H_{2} O_{2}$

$3 B a O + O_{2} ⟶ 2 B a O_{2}$

$B a O_{2} + H_{2} S O_{4} \to B a S O_{4} + H_{2} O_{2}$
as we know oxygen in peroxide is hare $- 1$ oxidotion.
SO, $B a O_{2}$ and $H_{2} O_{2}$ are peroxide have $- 1$ oxidation in oxygen.

Q. In which of the following reactions, there is no change in valency ?

4KClO3​⟶3KClO4​+KCl

SO2​+2H2​S⟶2H2​O+3S

BaO2​+H2​SO4​⟶BaSO4​+H2​O2​

3BaO+O2​⟶2BaO2​

BaO2​+H2​SO4​→BaSO4​+H2​O2​ as we know oxygen in peroxide is hare −1 oxidotion. SO, BaO2​ and H2​O2​ are peroxide have −1 oxidation in oxygen.

$4 K Cl O_{3} ⟶ 3 K Cl O_{4} + K Cl$

$S O_{2} + 2 H_{2} S ⟶ 2 H_{2} O + 3 S$

$B a O_{2} + H_{2} S O_{4} ⟶ B a S O_{4} + H_{2} O_{2}$

$3 B a O + O_{2} ⟶ 2 B a O_{2}$

$B a O_{2} + H_{2} S O_{4} \to B a S O_{4} + H_{2} O_{2}$
as we know oxygen in peroxide is hare $- 1$ oxidotion.
SO, $B a O_{2}$ and $H_{2} O_{2}$ are peroxide have $- 1$ oxidation in oxygen.