In which of the following pairs, there is greatest difference in the oxidation number of the underlined elements ?

Question

In which of the following pairs, there is greatest difference in the oxidation number of the underlined elements ? (A)  underlineNO2 and underlineN2O4 (B)  underlineP2O5 and underlineP4O10 (C)  underlineN2O and underlineNO (D)  underlineSO2 and underlineSO3

Tardigrade Admin · Accepted Answer

The oxidation number of elements have been mentioned in brackets as shown below:
a.

N O_{2} (x = 4)

and

N_{2} O_{4} (x = 4)

Difference in oxidation state of

N = 0

.
b.

P_{2} O_{5} (x = + 5)

and

P_{4} O_{10} (x = + 5)

Difference in oxidation state of

P

is zero.
c.

N_{2} O (x = 1)

and

NO (x = 2)

Difference in oxidation state of

N = 1

.
d.

S O_{2} (x = 4)

and

S O_{3} (x = 6)

Difference in oxidation state of

S = 2

.
Hence, the difference in oxidation states of underlined elements is greatest in

S O_{2}

.

Q. In which of the following pairs, there is greatest difference in the oxidation number of the underlined elements ?

$\underline{N} O_{2}$ and $\underline{N}_{2} O_{4}$

$\underline{P}_{2} O_{5}$ and $\underline{P}_{4} O_{10}$

$\underline{N}_{2} O$ and $\underline{N} O$

$\underline{S} O_{2}$ and $\underline{S} O_{3}$

Q. In which of the following pairs, there is greatest difference in the oxidation number of the underlined elements ?

N​O2​ and N​2​O4​

P​2​O5​ and P​4​O10​

N​2​O and N​O

S​O2​ and S​O3​

$\underline{N} O_{2}$ and $\underline{N}_{2} O_{4}$

$\underline{P}_{2} O_{5}$ and $\underline{P}_{4} O_{10}$

$\underline{N}_{2} O$ and $\underline{N} O$

$\underline{S} O_{2}$ and $\underline{S} O_{3}$