In which of the following ionization processes, the bond order has increased and the magnetic behaviour has changed?

Question

In which of the following ionization processes, the bond order has increased and the magnetic behaviour has changed? (A) C2 arrow C+2 (B) NO arrow NO+ (C) O2 arrow O+2 (D) N2 arrow N+2

Tardigrade Admin · Accepted Answer

In C2 - C2+ electron is removed from bonding molecular orbital so bond order decreases. In NO arrow NO+ , electron is removed from anti bonding molecular orbital so bond order increases and nature changes from paramagnetic to diamagnetic. Hence, (2) is correct.

Q. In which of the following ionization processes, the bond order has increased and the magnetic behaviour has changed?

$C_{2} \to C_{2}^{+}$

$NO \to N O^{+}$

$O_{2} \to O_{2}^{+}$

$N_{2} \to N_{2}^{+}$

In $C_{2} - C_{2}^{+}$ electron is removed from bonding molecular orbital so bond order decreases. In $NO \to N O^{+}$ , electron is removed from anti bonding molecular orbital so bond order increases and nature changes from paramagnetic to diamagnetic.
Hence, (2) is correct.

Q. In which of the following ionization processes, the bond order has increased and the magnetic behaviour has changed?

C2​→C2+​

NO→NO+

O2​→O2+​

N2​→N2+​

In C2​−C2+​ electron is removed from bonding molecular orbital so bond order decreases. In NO→NO+ , electron is removed from anti bonding molecular orbital so bond order increases and nature changes from paramagnetic to diamagnetic. Hence, (2) is correct.

$C_{2} \to C_{2}^{+}$

$NO \to N O^{+}$

$O_{2} \to O_{2}^{+}$

$N_{2} \to N_{2}^{+}$

In $C_{2} - C_{2}^{+}$ electron is removed from bonding molecular orbital so bond order decreases. In $NO \to N O^{+}$ , electron is removed from anti bonding molecular orbital so bond order increases and nature changes from paramagnetic to diamagnetic.
Hence, (2) is correct.