In which of the following compounds oxygen has highest oxidation state and in which it has lowest oxidation state? OF 2, H 2 O 2, KO 2, O 2 F 2

Question

In which of the following compounds oxygen has highest oxidation state and in which it has lowest oxidation state? OF 2, H 2 O 2, KO 2, O 2 F 2 (A) Highest = KO 2, lowest = H 2 O 2 (B) Highest = OF 2, lowest = K 2 O 2 (C) Highest = OF 2, lowest = KO 2 (D) Highest = KO 2, lowest = H 2 O

Tardigrade Admin · Accepted Answer

Oxidation number of oxygen in OF 2=+2 In KO 2=(-1/2)

Q. In which of the following compounds oxygen has highest oxidation state and in which it has lowest oxidation state? $O F_{2}, H_{2} O_{2}, K O_{2}, O_{2} F_{2}$

Highest $= K O_{2}$ , lowest $= H_{2} O_{2}$

Highest $= O F_{2}$ , lowest $= K_{2} O_{2}$

Highest $= O F_{2}$ , lowest $= K O_{2}$

Highest $= K O_{2}$ , lowest $= H_{2} O$

Oxidation number of oxygen in $O F_{2} = + 2$
In $K O_{2} = \frac{- 1}{2}$

Q. In which of the following compounds oxygen has highest oxidation state and in which it has lowest oxidation state? OF2​,H2​O2​,KO2​,O2​F2​

Highest =KO2​, lowest =H2​O2​

Highest =OF2​, lowest =K2​O2​

Highest =OF2​, lowest =KO2​

Highest =KO2​, lowest =H2​O