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Tardigrade
Question
Mathematics
In triangle A B C, tan A+ tan B+ tan C=6 and tan A tan B =2, then the values of tan A, tan B, tan C are
Q. In triangle
A
BC
,
tan
A
+
tan
B
+
tan
C
=
6
and
tan
A
tan
B
=
2
, then the values of
tan
A
,
tan
B
,
tan
C
are
310
183
Trigonometric Functions
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A
1,2,3
B
3,2/3,7/3
C
4,1 /2,3/2
D
none of these
Solution:
In a triangle,
tan
A
+
tan
B
+
tan
C
=
tan
A
tan
B
tan
C
...(i)
⇒
6
=
2
tan
C
or
tan
C
=
3
Also
tan
A
+
tan
B
=
6
−
3
=
3
...(ii)
By Eqs. (i) and (ii),
tan
A
and
tan
B
are roots of
x
2
−
3
x
+
2
=
0
.
Thus,
tan
A
,
tan
B
=
2
,
1
or 1,2 and
tan
C
=
3