In the setup shown, a 200N block is supported in equilibrium with the help of strings and a spring. A point O , the strings knotted. Extension in the spring is 4cm . Force constant of the spring is closest to [g = 10 m / s2]

Question

In the setup shown, a 200N block is supported in equilibrium with the help of strings and a spring. A point O , the strings knotted. Extension in the spring is 4cm . Force constant of the spring is closest to [g = 10 m / s2] <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-8d6pjqerni3qxyfu.jpg" /> (A) 30N/m (B) 2500N/m (C) 3000N/m (D) 4000N/m

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-8d6pjqerni3qdhyq.jpg" /> In equilibrium Acc to Lami's theorem (200/sin (. 180 - 90 .))=(T1/sin (. 90 + 53 .)) (200/1)=(T1/cos 53 ° ) T1=40× 3= Kx⇒ K=3000N/m

Q. In the setup shown, a $200 N$ block is supported in equilibrium with the help of strings and a spring. A point $O$ , the strings knotted. Extension
in the spring is $4 c m$ . Force constant of the spring is closest to $[g = 10 m / s^{2}]$

$30 N / m$

$2500 N / m$

$3000 N / m$

$4000 N / m$

In equilibrium Acc to Lami's theorem
$\frac{200}{s in ( 180 - 90 )} = \frac{T _{1}}{s in ( 90 + 53 )}$
$\frac{200}{1} = \frac{T _{1}}{cos 5 3 ^{\circ}}$
$T_{1} = 40 \times 3 =$
$K x \Rightarrow K = 3000 N / m$

Q. In the setup shown, a 200N block is supported in equilibrium with the help of strings and a spring. A point O , the strings knotted. Extension in the spring is 4cm . Force constant of the spring is closest to [g=10m/s2]

30N/m

2500N/m

3000N/m

4000N/m