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Tardigrade
Question
Chemistry
In the series of reaction X and Y are respectively are C6H5NH2 oversetN a N O2 / H C l arrow X oversetH N O2 arrow Y+N2+HCl
Q. In the series of reaction X and Y are respectively are
C
6
H
5
N
H
2
→
N
a
N
O
2
/
H
Cl
X
→
H
N
O
2
Y
+
N
2
+
H
Cl
1486
218
NTA Abhyas
NTA Abhyas 2020
Amines
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A
C
6
H
5
−
N
=
N
−
C
6
H
5
,
C
6
H
5
N
2
⊕
C
l
Θ
0%
B
C
6
H
5
N
2
⊕
C
l
Θ
,
C
6
H
5
−
N
=
N
−
C
6
H
5
0%
C
C
6
H
5
N
2
⊕
C
l
Θ
,
C
6
H
5
N
O
2
100%
D
C
6
H
5
N
O
2
,
C
6
H
6
0%
Solution:
C
6
H
5
N
H
2
→
N
a
N
O
2
/
H
Cl
(
X
)
C
6
H
5
N
2
+
C
l
−
→
H
N
O
2
(
Y
)
C
6
H
5
N
O
2
+
N
2
+
H
Cl