In the rectangle shown below, the two corners have charges q1=-5 μ C and q2=+2.0 μ C . The work done in moving a charge +3.0 μ C from B to A is (take .1 / 4 π ε0=1010 N - m 2 / C 2)

Question

In the rectangle shown below, the two corners have charges q1=-5 μ C and q2=+2.0 μ C . The work done in moving a charge +3.0 μ C from B to A is (take .1 / 4 π ε0=1010 N - m 2 / C 2) (A) 2.8 J (B) 3.5 J (C) 4.5 J (D) 5.5 J

Tardigrade Admin · Accepted Answer

Work done W=3 × 10-6(VA-VB); where VA=1010[((-5 × 10-6)/15 × 10-2)+(2 × 10-6/5 × 10-2)] =(1/15) × 106 volt and VB=1010[((2 × 10-6)/15 × 10-2)-(5 × 10-6/5 × 10-2)] =-(13/15) × 106 volt ∴ W=3 × 10-6[(1/15) × 106-(-(13/15) × 106)] =2.8 J

Q. In the rectangle shown below, the two corners have charges q1​=−5μC and q2​=+2.0μC. The work done in moving a charge +3.0μC from B to A is (take 1/4πε0​=1010N−m2/C2)

2.8 J

3.5 J

4.5 J

5.5 J

Work done W=3×10−6(VA​−VB​); where VA​=1010[15×10−2(−5×10−6)​+5×10−22×10−6​] =151​×106 volt and VB​=1010[15×10−2(2×10−6)​−5×10−25×10−6​] =−1513​×106 volt ∴W=3×10−6[151​×106−(−1513​×106)] =2.8J

Q. In the rectangle shown below, the two corners have charges $q_{1} = - 5 μ C$ and $q_{2} = + 2.0 μ C .$ The work done in moving a charge $+ 3.0 μ C$ from $B$ to $A$ is (take $1/4 π ε_{0} = 1 0^{10} N - m^{2} / C^{2})$