In the reaction of formation of sulphur trioxide by contact process 2SO2 + O2 leftharpoons 2SO3 the rate of reaction was measured as (d[O2]/dt) = 2.5×10-4mol L-1 s-1. The rate of reaction in terms of [SO2] in mol L-1s-1 will be :

Question

In the reaction of formation of sulphur trioxide by contact process 2SO2 + O2 leftharpoons 2SO3 the rate of reaction was measured as (d[O2]/dt) = 2.5×10-4mol L-1 s-1. The rate of reaction in terms of [SO2] in mol L-1s-1 will be : (A) -1.25 × 10-4 (B) -2.50 × 10-4 (C) -3.75 × 10-4 (D) -5.00 × 10-4

Tardigrade Admin · Accepted Answer

-(1/2)(d/d t) [SO2]=-(d/d t) [O2] ⇒ (d/d t) [So2]=-2×2.5×10-4 =-5×10-4

Q. In the reaction of formation of sulphur trioxide by contact process $2 S O_{2} + O_{2} ⇌ 2 S O_{3}$ the rate of reaction was measured as $\frac{d [ O _{2} ]}{d t} = 2.5 \times 1 0^{- 4} m o l L^{- 1} s^{- 1} .$ The rate of reaction in terms of $[S O_{2}]$ in mol $L^{- 1} s^{- 1}$ will be :

$- 1.25 \times 1 0^{- 4}$

$- 2.50 \times 1 0^{- 4}$

$- 3.75 \times 1 0^{- 4}$

$- 5.00 \times 1 0^{- 4}$

$- \frac{1}{2} \frac{d}{d t} [S O_{2}] = - \frac{d}{d t} [O_{2}]$

$\Rightarrow \frac{d}{d t} [S o_{2}] = - 2 \times 2.5 \times 1 0^{- 4}$

$= - 5 \times 1 0^{- 4}$

Q. In the reaction of formation of sulphur trioxide by contact process 2SO2​+O2​⇌2SO3​ the rate of reaction was measured as dtd[O2​]​=2.5×10−4molL−1s−1. The rate of reaction in terms of [SO2​] in mol L−1s−1 will be :

−1.25×10−4

−2.50×10−4

−3.75×10−4

−5.00×10−4