In the reaction (CH)3-CH=(CH)2 overset(Cl)2 / 500 ° C arrow (A)(Na/dry ether )(B)

Question

In the reaction (CH)3-CH=(CH)2 overset(Cl)2 / 500 ° C arrow (A)(Na/dry ether )(B) (A) CH3-CH=CH-OH (B) CH2=CH-CH2-CH2-CH=CH2 (C) HO-CH2-CH=CH2 (D) <img class="img-fluid question-image" alt="Option 4" src="https://cdn.tardigrade.in/q/nta/c-fbps8owuxvvli4qz.jpg" />

Tardigrade Admin · Accepted Answer

CH3-CH=CH2 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-fbps8owuxvvlzih4.jpg" />

Q. In the reaction
$(C H)_{3} - C H = (C H)_{2} \to (Cl)_{2} /50 0^{\circ} C (A) \frac{N a}{d rye t h er} (B)$

$C H_{3} - C H = C H - O H$

$C H_{2} = C H - C H_{2} - C H_{2} - C H = C H_{2}$

$H O - C H_{2} - C H = C H_{2}$

$C H_{3} - C H = C H_{2}$

Q. In the reaction (CH)3​−CH=(CH)2​→(Cl)2​/500∘C(A)dryetherNa​(B)

CH3​−CH=CH−OH

CH2​=CH−CH2​−CH2​−CH=CH2​

HO−CH2​−CH=CH2​

CH3​−CH=CH2​

Q. In the reaction
$(C H)_{3} - C H = (C H)_{2} \to (Cl)_{2} /50 0^{\circ} C (A) \frac{N a}{d rye t h er} (B)$

$C H_{3} - C H = C H - O H$

$C H_{2} = C H - C H_{2} - C H_{2} - C H = C H_{2}$

$H O - C H_{2} - C H = C H_{2}$

$C H_{3} - C H = C H_{2}$