In the reaction, 2A arrow Product, the concentration of A decreases from 7.0 mole/ litre to 6.0 mole/litre in 5 minutes. The rate of reaction is

Question

In the reaction, 2A arrow Product, the concentration of A decreases from 7.0 mole/ litre to 6.0 mole/litre in 5 minutes. The rate of reaction is (A) 1.0 mol L -1 min -1 (B)  0.05 mol L -1 min -1 (C)  0.2 mol L -1 min -1 (D)  0.1 mol L -1 min -1

Tardigrade Admin · Accepted Answer

Rate =-(1/2) (d[A]/d t) =-(1/2) ((7-6)/5)=-0.1 mol L -1 min -1 Negative sign signifies the decrease in concentration

Q. In the reaction, $2 A \to$ Product, the concentration of A decreases from $7.0 m o l e / l i t re$ to $6.0 m o l e / l i t re$ in $5$ minutes. The rate of reaction is

$1.0 m o l L^{- 1} mi n^{- 1}$

$0.05 m o l L^{- 1} mi n^{- 1}$

$0.2 m o l L^{- 1} mi n^{- 1}$

$0.1 m o l L^{- 1} mi n^{- 1}$

Rate $= - \frac{1}{2} \frac{d [ A ]}{d t}$
$= - \frac{1}{2} \frac{( 7 - 6 )}{5} = - 0.1 m o l L^{- 1} min^{- 1}$
Negative sign signifies the decrease in concentration

Q. In the reaction, 2A→ Product, the concentration of A decreases from 7.0mole/litre to 6.0mole/litre in 5 minutes. The rate of reaction is

1.0molL−1min−1

0.05molL−1min−1

0.2molL−1min−1

0.1molL−1min−1