Question

In the reaction, ${}_{12}^{24}Mg+{}_2^{4}He\to {}_{14}^{x}Si+{}_0^{1}n,x$ is

• A. 28
• B. 27
• C. 26
• D. 22

Answer 1

Answer: (B)

${}_{12}^{24}Mg+{}_2^{4}He\to {}_{14}^{x}Si+{}_0^{1}n$
According to mass number conservation, we get
$24+4=x+1$
or $x=27$