In the LC circuit shown below, the current is in direction as shown and the charges on the capacitor plates have the sign as shown. At this instant

Question

In the LC circuit shown below, the current is in direction as shown and the charges on the capacitor plates have the sign as shown. At this instant <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-vb8uixf4oodl.png" /> (A) I is increasing Q is increasing (B) I is increasing Q is decreasing (C) I is decreasing Q is increasing (D) I is decreasing and Q is decreasing

Tardigrade Admin · Accepted Answer

As clearly ‘ Q ’ is increasing so electric field energy in capacitor must be increasing. And hence, magnetic field energy in inductor must be decreasing. So I is decreasing.

Q. In the $L C$ circuit shown below, the current is in direction as shown and the charges on the capacitor plates have the sign as shown. At this instant

$I$ is increasing $Q$ is increasing

$I$ is increasing $Q$ is decreasing

$I$ is decreasing $Q$ is increasing

$I$ is decreasing and $Q$ is decreasing

As clearly ‘ $Q$ ’ is increasing so electric field energy in capacitor must be increasing. And hence, magnetic field energy in inductor must be decreasing. So $I$ is decreasing.

Q. In the LC circuit shown below, the current is in direction as shown and the charges on the capacitor plates have the sign as shown. At this instant

I is increasing Q is increasing

I is increasing Q is decreasing

I is decreasing Q is increasing

I is decreasing and Q is decreasing