In the hydrogen atom, the electron is moving around the nucleus with velocity 2.18 × 106 m s- 1 in an orbit of radius 0.528 overset° A . The acceleration of the electron is

Question

In the hydrogen atom, the electron is moving around the nucleus with velocity 2.18 × 106 m s- 1 in an orbit of radius 0.528 overset° A . The acceleration of the electron is (A) 9 × 1018 m s- 2 (B) 9 × 1022 m s- 2 (C) 9 × 10- 22 m s- 2 (D) 9 × 1012 m s- 2

Tardigrade Admin · Accepted Answer

Given, v=2.18 × 106 m s- 1, r=0.528 × 10- 10 m Acceleration of electron moving round the nucleus a = ((2.18 × (10)6)2/0.528 × (10)- 10)≈ 9 × 1022 m s- 2

Q. In the hydrogen atom, the electron is moving around the nucleus with velocity $2.18 \times 1 0^{6} m s^{- 1}$ in an orbit of radius $0.528 A^{\circ}$ . The acceleration of the electron is

$9 \times 1 0^{18} m s^{- 2}$

$9 \times 1 0^{22} m s^{- 2}$

$9 \times 1 0^{- 22} m s^{- 2}$

$9 \times 1 0^{12} m s^{- 2}$

Given, $v = 2.18 \times 1 0^{6} m s^{- 1}, r = 0.528 \times 1 0^{- 10} m$
Acceleration of electron moving round the nucleus
$a =$ $\frac{( 2.18 \times ( 10 ) ^{6} ) ^{2}}{0.528 \times ( 10 ) ^{- 10}} \approx$ $9 \times 1 0^{22} m s^{- 2}$

Q. In the hydrogen atom, the electron is moving around the nucleus with velocity 2.18×106ms−1 in an orbit of radius 0.528A∘ . The acceleration of the electron is

9×1018ms−2

9×1022ms−2

9×10−22ms−2

9×1012ms−2