In the given (V - T) diagram, what is the relation between pressures P1 and P2 ?

Question

In the given (V - T) diagram, what is the relation between pressures P1 and P2 ? (A) P2< P1 (B) Cannot be predicted (C) P2=P1 (D) P2> P1

Tardigrade Admin · Accepted Answer

According to ideal gas equation PV = nRT or V=(n R T/P) For an isobaric process, P= constant and ∨ ∞ T Therefore, V - T graph is a straight line passing through origin. Slope of this line is inversely proportional to P. In the given figure,

( text Slope )2 >( text Slope )1 P2< P1

Q. In the given $(V - T)$ diagram, what is the relation between pressures $P_{1}$ and $P_{2} ?$

$P_{2} < P_{1}$

Cannot be predicted

$P_{2} = P_{1}$

$P_{2} > P_{1}$

Q. In the given (V−T) diagram, what is the relation between pressures P1​ and P2​?

P2​<P1​

Cannot be predicted

P2​=P1​

P2​>P1​

According to ideal gas equation PV=nRT or V=PnRT​ For an isobaric process, P= constant and ∨∞T Therefore, V−T graph is a straight line passing through origin. Slope of this line is inversely proportional to P. In the given figure, ( Slope )2​>( Slope )1​ P2​<P1​

Q. In the given $(V - T)$ diagram, what is the relation between pressures $P_{1}$ and $P_{2} ?$

$P_{2} < P_{1}$

$P_{2} = P_{1}$

$P_{2} > P_{1}$